The question involves two trains, A and B, which are traveling toward each other, with given speeds and times to reach their respective stations after meeting. From the documents, we note that: 1. Train A reaches station Y in 10 minutes. 2. After meeting Train A, Train B takes 9 minutes to reach station X. To determine the time taken by Train B to travel from station Y to station X after they meet, we apply the concept of relative speed and the proportionality based on the time taken by each train to reach its destination after meeting. Given that: - Time taken by Train A after meeting Train B = 10 minutes - Time taken by Train B after meeting Train A = 9 minutes Using the ratio of their respective times to estimate the distance or speed comparison, we find: - The ratio of speed can be derived from the square roots of the time ratios as \( SA/SB = (TB)^{1/2} / (TA)^{1/2} \). Since we have established that: - The time intervals are (10 and 9), hence the speed ratio indicates that for every 10 units of distance Train A travels, Train B travels 9 units. To find out the total time taken by Train B from station Y to X after they meet: - The options provided for total time taken by Train B to reach station X from Y are: 6, 15, 10, and 12 minutes. Given the context, the total time that corresponds correctly to the calculation and ratio found from proportionality is 6 minutes for Train B after meeting Train A to reach its destination. Therefore, the answer is: 6 minutes. (Explanation derived from the gathered information on speed and time ratios pertinent to the traveling time between trains.)